c语言md5函数,c语言md5加密函数

请教MD5算法 用C语言实现

#include stdio.h

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#include stdlib.h

#include string.h

#if defined(__APPLE__)

#  define COMMON_DIGEST_FOR_OPENSSL

#  include CommonCrypto/CommonDigest.h

#  define SHA1 CC_SHA1

#else

#  include openssl/md5.h

#endif

// 这是我自己写的函数，用于计算MD5

// 参数 str：要转换的字符串

// 参数 lengthL: 字符串的长度 可以用 strlen(str) 直接获取参数str的长度

// 返回值：MD5字符串

char *str2md5(const char * str, int length) {

int n;

MD5_CTX c;

unsigned char digest[16];

char *out = (char*)malloc(33);

MD5_Init(c);

while (length  0) {

if (length  512) {

MD5_Update(c, str, 512);

} else {

MD5_Update(c, str, length);

}

length -= 512;

str += 512;

}

MD5_Final(digest, c);

for (n = 0; n  16; ++n) {

snprintf((out[n*2]), 16*2, "%02x", (unsigned int)digest[n]);

}

return out;

}

int main(int argc, char **argv) {

char *output = str2md5("hello", strlen("hello"));

printf("%s\n", output);

// 上面会输出 hello的MD5字符串：

// 5d41402abc4b2a76b9719d911017c592

free(output);

return 0;

}

C语言求文件MD5的函数用法

#ifndef MD5_H

#define MD5_H

typedef struct

{

unsigned int count[2];

unsigned int state[4];

unsigned char buffer[64];

}MD5_CTX;

#define F(x,y,z) ((x y) | (~x z))

#define G(x,y,z) ((x z) | (y ~z))

#define H(x,y,z) (x^y^z)

#define I(x,y,z) (y ^ (x | ~z))

#define ROTATE_LEFT(x,n) ((x n) | (x (32-n)))

#define FF(a,b,c,d,x,s,ac) \

{ \

a += F(b,c,d) + x + ac; \

a = ROTATE_LEFT(a,s); \

a += b; \

}

#define GG(a,b,c,d,x,s,ac) \

{ \

a += G(b,c,d) + x + ac; \

a = ROTATE_LEFT(a,s); \

a += b; \

}

#define HH(a,b,c,d,x,s,ac) \

{ \

a += H(b,c,d) + x + ac; \

a = ROTATE_LEFT(a,s); \

a += b; \

}

#define II(a,b,c,d,x,s,ac) \

{ \

a += I(b,c,d) + x + ac; \

a = ROTATE_LEFT(a,s); \

a += b; \

}

void MD5Init(MD5_CTX *context);

void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen);

void MD5Final(MD5_CTX *context,unsigned char digest[16]);

void MD5Transform(unsigned int state[4],unsigned char block[64]);

void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len);

void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len);

#endif

源文件md5.c

#include memory.h

#include "md5.h"

unsigned char PADDING[]={0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};

void MD5Init(MD5_CTX *context)

{

context-count[0] = 0;

context-count[1] = 0;

context-state[0] = 0x67452301;

context-state[1] = 0xEFCDAB89;

context-state[2] = 0x98BADCFE;

context-state[3] = 0x10325476;

}

void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen)

{

unsigned int i = 0,index = 0,partlen = 0;

index = (context-count[0] 3) 0x3F;

partlen = 64 - index;

context-count[0] += inputlen 3;

if(context-count[0] (inputlen 3))

context-count[1]++;

context-count[1] += inputlen 29;

if(inputlen = partlen)

{

memcpy(context-buffer[index],input,partlen);

MD5Transform(context-state,context-buffer);

for(i = partlen;i+64 = inputlen;i+=64)

MD5Transform(context-state,input[i]);

index = 0;

}

else

{

i = 0;

}

memcpy(context-buffer[index],input[i],inputlen-i);

}

void MD5Final(MD5_CTX *context,unsigned char digest[16])

{

unsigned int index = 0,padlen = 0;

unsigned char bits[8];

index = (context-count[0] 3) 0x3F;

padlen = (index 56)?(56-index):(120-index);

MD5Encode(bits,context-count,8);

MD5Update(context,PADDING,padlen);

MD5Update(context,bits,8);

MD5Encode(digest,context-state,16);

}

void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len)

{

unsigned int i = 0,j = 0;

while(j len)

{

output[j] = input[i] 0xFF;

output[j+1] = (input[i] 8) 0xFF;

output[j+2] = (input[i] 16) 0xFF;

output[j+3] = (input[i] 24) 0xFF;

i++;

j+=4;

}

}

void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len)

{

unsigned int i = 0,j = 0;

while(j len)

{

output[i] = (input[j]) |

(input[j+1] 8) |

(input[j+2] 16) |

(input[j+3] 24);

i++;

j+=4;

}

}

void MD5Transform(unsigned int state[4],unsigned char block[64])

{

unsigned int a = state[0];

unsigned int b = state[1];

unsigned int c = state[2];

unsigned int d = state[3];

unsigned int x[64];

MD5Decode(x,block,64);

FF(a, b, c, d, x[ 0], 7, 0xd76aa478); /* 1 */

FF(d, a, b, c, x[ 1], 12, 0xe8c7b756); /* 2 */

FF(c, d, a, b, x[ 2], 17, 0x242070db); /* 3 */

FF(b, c, d, a, x[ 3], 22, 0xc1bdceee); /* 4 */

FF(a, b, c, d, x[ 4], 7, 0xf57c0faf); /* 5 */

FF(d, a, b, c, x[ 5], 12, 0x4787c62a); /* 6 */

FF(c, d, a, b, x[ 6], 17, 0xa8304613); /* 7 */

FF(b, c, d, a, x[ 7], 22, 0xfd469501); /* 8 */

FF(a, b, c, d, x[ 8], 7, 0x698098d8); /* 9 */

FF(d, a, b, c, x[ 9], 12, 0x8b44f7af); /* 10 */

FF(c, d, a, b, x[10], 17, 0xffff5bb1); /* 11 */

FF(b, c, d, a, x[11], 22, 0x895cd7be); /* 12 */

FF(a, b, c, d, x[12], 7, 0x6b901122); /* 13 */

FF(d, a, b, c, x[13], 12, 0xfd987193); /* 14 */

FF(c, d, a, b, x[14], 17, 0xa679438e); /* 15 */

FF(b, c, d, a, x[15], 22, 0x49b40821); /* 16 */

如何对字符串进行MD5加密,用C语言实现,给出源代码和加密函数

/*四个32bits数,用于存放最终计算得到的消息摘要.当消息长度512bits时,也用于存放每个512bits的中间结果*/ UINT4 state[4]; /*存储原始信息的bits数长度,不包括填充的bits,最长为2^64 bits*/ UINT4 count[2]; /*存放输入的信息的缓冲区,512bits*/ unsigned char buffer[64];} MD5_CTX;static void MD5Transform(UINT4[4], unsigned char[64]); static void Encode(unsigned char *, UINT4 *, unsigned int); static void Decode(UINT4 *, unsigned char *, unsigned int);/*用于bits填充的缓冲区,当欲加密的信息的bits数被512除其余数为448时,需要填充的bits的最大值为512=64*8*/ static unsigned char PADDING[64] = { 0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0};/*接下来的这几个宏定义是md5算法规定的,就是对信息进行md5加密都要做的运算*/ #define F(x, y, z) (((x) (y)) | ((~x) (z))) #define G(x, y, z) (((x) (z)) | ((y) (~z))) #define H(x, y, z) ((x) ^ (y) ^ (z)) #define I(x, y, z) ((y) ^ ((x) | (~z))) #define ROTATE_LEFT(x, n) (((x) (n)) | ((x) (32-(n)))) #define FF(a, b, c, d, x, s, ac) {\ (a) += F ((b), (c), (d)) + (x) + (UINT4)(ac);\ (a) = ROTATE_LEFT ((a), (s));\ (a) += (b);\}#define GG(a, b, c, d, x, s, ac) {\ (a) += G ((b), (c), (d)) + (x) + (UINT4)(ac);\ (a) = ROTATE_LEFT ((a), (s));\ (a) += (b);\}#define HH(a, b, c, d, x, s, ac) {\ (a) += H ((b), (c), (d)) + (x) + (UINT4)(ac);\ (a) = ROTATE_LEFT ((a), (s));\ (a) += (b);\}#define II(a, b, c, d, x, s, ac) {\ (a) += I ((b), (c), (d)) + (x) + (UINT4)(ac);\

求c语言下获取一个字符串MD5值得函数

1. md5.h：

＃pragma once

typedef unsigned long int UINT32;

typedef unsigned short int UINT16;

/× MD5 context. */

typedef struct {

UINT32 state[4]; /× state (ABCD) */

UINT32 count[2]; /× number of bits, modulo 2^64 (lsb first) */

unsigned char buffer[64]; /× input buffer */

} MD5_CTX;

void MD5Init (MD5_CTX *);

void MD5Update (MD5_CTX *, unsigned char *, unsigned int);

void MD5Final (unsigned char [16], MD5_CTX *);

——————————————————————————

2. md5.cpp：

＃include "md5.h"

＃include "memory.h"

＃define S11 7

＃define S12 12

＃define S13 17

＃define S14 22

＃define S21 5

＃define S22 9

＃define S23 14

＃define S24 20

＃define S31 4

＃define S32 11

＃define S33 16

＃define S34 23

＃define S41 6

＃define S42 10

＃define S43 15

＃define S44 21

static void MD5Transform (UINT32 a[4], unsigned char b[64]);

static void Encode (unsigned char *, UINT32 *, unsigned int);

static void Decode (UINT32 *, unsigned char *, unsigned int);

static unsigned char PADDING[64] = {

0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0

};

＃define F(x, y, z) (((x) (y)) | ((~x) (z)))

＃define G(x, y, z) (((x) (z)) | ((y) (~z)))

＃define H(x, y, z) ((x) ^ (y) ^ (z))

＃define I(x, y, z) ((y) ^ ((x) | (~z)))

＃define ROTATE_LEFT(x, n) (((x) (n)) | ((x) (32-(n))))

＃define FF(a, b, c, d, x, s, ac) {

(a) += F ((b), (c), (d)) + (x) + (UINT32)(ac);

(a) = ROTATE_LEFT ((a), (s));

(a) += (b);

}

＃define GG(a, b, c, d, x, s, ac) {

(a) += G ((b), (c), (d)) + (x) + (UINT32)(ac);

(a) = ROTATE_LEFT ((a), (s));

(a) += (b);

}

＃define HH(a, b, c, d, x, s, ac) {

(a) += H ((b), (c), (d)) + (x) + (UINT32)(ac);

(a) = ROTATE_LEFT ((a), (s));

(a) += (b);

}

＃define II(a, b, c, d, x, s, ac) {

(a) += I ((b), (c), (d)) + (x) + (UINT32)(ac);

(a) = ROTATE_LEFT ((a), (s));

(a) += (b);

}

void MD5Init (MD5_CTX *context)

{

context-count[0] = context-count[1] = 0;

context-state[0] = 0x67452301;

context-state[1] = 0xefcdab89;

context-state[2] = 0x98badcfe;

context-state[3] = 0x10325476;

}

void MD5Update (MD5_CTX *context, unsigned char *input, unsigned int inputLen)

{

unsigned int i, index, partLen;

index = (unsigned int)((context-count[0] 3) 0x3F);

if ((context-count[0] += ((UINT32)inputLen 3))

((UINT32)inputLen 3))

context-count[1]++;

context-count[1] += ((UINT32)inputLen 29);

partLen = 64 - index;

if (inputLen = partLen) {

memcpy((unsigned char *)context-buffer[index], (unsigned char *)input, partLen);

MD5Transform (context-state, context-buffer);

for (i = partLen; i + 63 inputLen; i += 64)

MD5Transform (context-state, input[i]);

index = 0;

}

else

i = 0;

memcpy((unsigned char *)context-buffer[index], (unsigned char *)input[i],

inputLen-i);

}

void MD5Final (unsigned char digest[16], MD5_CTX * context)

{

unsigned char bits[8];

unsigned int index, padLen;

Encode (bits, context-count, 8);

index = (unsigned int)((context-count[0] 3) 0x3f);

padLen = (index 56) ? (56 - index) : (120 - index);

MD5Update (context, PADDING, padLen);

MD5Update (context, bits, 8);

Encode (digest, context-state, 16);

memset ((unsigned char *)context, 0, sizeof (*context));

}

static void MD5Transform (UINT32 state[4], unsigned char block[64])

{

UINT32 a = state[0], b = state[1], c = state[2], d = state[3], x[16];

Decode (x, block, 64);

/× Round 1 */

FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /× 1 */

FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /× 2 */

FF (c, d, a, b, x[ 2], S13, 0x242070db); /× 3 */

FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /× 4 */

FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /× 5 */

FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /× 6 */

FF (c, d, a, b, x[ 6], S13, 0xa8304613); /× 7 */

FF (b, c, d, a, x[ 7], S14, 0xfd469501); /× 8 */

FF (a, b, c, d, x[ 8], S11, 0x698098d8); /× 9 */

FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /× 10 */

FF (c, d, a, b, x[10], S13, 0xffff5bb1); /× 11 */

FF (b, c, d, a, x[11], S14, 0x895cd7be); /× 12 */

FF (a, b, c, d, x[12], S11, 0x6b901122); /× 13 */

FF (d, a, b, c, x[13], S12, 0xfd987193); /× 14 */

FF (c, d, a, b, x[14], S13, 0xa679438e); /× 15 */

FF (b, c, d, a, x[15], S14, 0x49b40821); /× 16 */

/× Round 2 */

GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /× 17 */

GG (d, a, b, c, x[ 6], S22, 0xc040b340); /× 18 */

GG (c, d, a, b, x[11], S23, 0x265e5a51); /× 19 */

GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /× 20 */

GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /× 21 */

GG (d, a, b, c, x[10], S22, 0x2441453); /× 22 */

GG (c, d, a, b, x[15], S23, 0xd8a1e681); /× 23 */

GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /× 24 */

GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /× 25 */

GG (d, a, b, c, x[14], S22, 0xc33707d6); /× 26 */

GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /× 27 */

GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /× 28 */

GG (a, b, c, d, x[13], S21, 0xa9e3e905); /× 29 */

GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /× 30 */

GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /× 31 */

GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /× 32 */

/× Round 3 */

HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /× 33 */

HH (d, a, b, c, x[ 8], S32, 0x8771f681); /× 34 */

HH (c, d, a, b, x[11], S33, 0x6d9d6122); /× 35 */

HH (b, c, d, a, x[14], S34, 0xfde5380c); /× 36 */

HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /× 37 */

HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /× 38 */

HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /× 39 */

HH (b, c, d, a, x[10], S34, 0xbebfbc70); /× 40 */

HH (a, b, c, d, x[13], S31, 0x289b7ec6); /× 41 */

HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /× 42 */

HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /× 43 */

HH (b, c, d, a, x[ 6], S34, 0x4881d05); /× 44 */

HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /× 45 */

HH (d, a, b, c, x[12], S32, 0xe6db99e5); /× 46 */

HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /× 47 */

HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /× 48 */

/× Round 4 */

II (a, b, c, d, x[ 0], S41, 0xf4292244); /× 49 */

II (d, a, b, c, x[ 7], S42, 0x432aff97); /× 50 */

II (c, d, a, b, x[14], S43, 0xab9423a7); /× 51 */

II (b, c, d, a, x[ 5], S44, 0xfc93a039); /× 52 */

II (a, b, c, d, x[12], S41, 0x655b59c3); /× 53 */

II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /× 54 */

II (c, d, a, b, x[10], S43, 0xffeff47d); /× 55 */

II (b, c, d, a, x[ 1], S44, 0x85845dd1); /× 56 */

II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /× 57 */

II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /× 58 */

II (c, d, a, b, x[ 6], S43, 0xa3014314); /× 59 */

II (b, c, d, a, x[13], S44, 0x4e0811a1); /× 60 */

II (a, b, c, d, x[ 4], S41, 0xf7537e82); /× 61 */

II (d, a, b, c, x[11], S42, 0xbd3af235); /× 62 */

II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /× 63 */

II (b, c, d, a, x[ 9], S44, 0xeb86d391); /× 64 */

state[0] += a;

state[1] += b;

state[2] += c;

state[3] += d;

memset ((unsigned char *)x, 0, sizeof (x));

}

static void Encode (unsigned char *output, UINT32 *input, unsigned int len)

{

unsigned int i, j;

for (i = 0, j = 0; j len; i++, j += 4) {

output[j] = (unsigned char)(input[i] 0xff);

output[j+1] = (unsigned char)((input[i] 8) 0xff);

output[j+2] = (unsigned char)((input[i] 16) 0xff);

output[j+3] = (unsigned char)((input[i] 24) 0xff);

}

}

static void Decode (UINT32 *output, unsigned char *input, unsigned int len)

{

unsigned int i, j;

for (i = 0, j = 0; j len; i++, j += 4)

output[i] = ((UINT32)input[j]) | (((UINT32)input[j+1]) 8) |

(((UINT32)input[j+2]) 16) | (((UINT32)input[j+3]) 24);

}

——————————————————————————

＃include stdio.h

＃include string.h

＃include "md5.h"

int main ()

{

char tmp[128];

unsigned char digest[16];

MD5_CTX context;

scanf("%s",tmp);

MD5Init (context);

MD5Update (context, (unsigned char*)tmp, strlen(tmp));

MD5Final (digest,context);

printf("MD5Value:");

for(int i=0; i16; ++i)

{

printf("%02X",digest[i]);

}

printf(" ");

return 0;

}

VS2013中c语言md5加密函数怎么调用?

1、主要就是调用库函数，MD5加密说到底也是函数计算，没有什么思路的问题，了解md5的发明算法，本质是一个数学问题。

2、例程：

#ifndef MD5_H

#define MD5_H

typedef struct

{

unsigned int count[2];

unsigned int state[4];

unsigned char buffer[64];   

}MD5_CTX;

#define F(x,y,z) ((x  y) | (~x  z))

#define G(x,y,z) ((x  z) | (y  ~z))

#define H(x,y,z) (x^y^z)

#define I(x,y,z) (y ^ (x | ~z))

#define ROTATE_LEFT(x,n) ((x  n) | (x  (32-n)))

#define FF(a,b,c,d,x,s,ac) \

{ \

a += F(b,c,d) + x + ac; \

a = ROTATE_LEFT(a,s); \

a += b; \

}

#define GG(a,b,c,d,x,s,ac) \

{ \

a += G(b,c,d) + x + ac; \

a = ROTATE_LEFT(a,s); \

a += b; \

}

#define HH(a,b,c,d,x,s,ac) \

{ \

a += H(b,c,d) + x + ac; \

a = ROTATE_LEFT(a,s); \

a += b; \

}

#define II(a,b,c,d,x,s,ac) \

{ \

a += I(b,c,d) + x + ac; \

a = ROTATE_LEFT(a,s); \

a += b; \

}                                            

void MD5Init(MD5_CTX *context);

void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen);

void MD5Final(MD5_CTX *context,unsigned char digest[16]);

void MD5Transform(unsigned int state[4],unsigned char block[64]);

void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len);

void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len);

#endif

源文件md5.c

#include memory.h

#include "md5.h"

unsigned char PADDING[]={0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};

void MD5Init(MD5_CTX *context)

{

context-count[0] = 0;

context-count[1] = 0;

context-state[0] = 0x67452301;

context-state[1] = 0xEFCDAB89;

context-state[2] = 0x98BADCFE;

context-state[3] = 0x10325476;

}

void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen)

{

unsigned int i = 0,index = 0,partlen = 0;

index = (context-count[0]  3)  0x3F;

partlen = 64 - index;

context-count[0] += inputlen  3;

if(context-count[0]  (inputlen  3))

context-count[1]++;

context-count[1] += inputlen  29;

if(inputlen = partlen)

{

memcpy(context-buffer[index],input,partlen);

MD5Transform(context-state,context-buffer);

for(i = partlen;i+64 = inputlen;i+=64)

MD5Transform(context-state,input[i]);

index = 0;        

}  

else

{

i = 0;

}

memcpy(context-buffer[index],input[i],inputlen-i);

}

void MD5Final(MD5_CTX *context,unsigned char digest[16])

{

unsigned int index = 0,padlen = 0;

unsigned char bits[8];

index = (context-count[0]  3)  0x3F;

padlen = (index  56)?(56-index):(120-index);

MD5Encode(bits,context-count,8);

MD5Update(context,PADDING,padlen);

MD5Update(context,bits,8);

MD5Encode(digest,context-state,16);

}

void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len)

{

unsigned int i = 0,j = 0;

while(j  len)

{

output[j] = input[i]  0xFF;  

output[j+1] = (input[i]  8)  0xFF;

output[j+2] = (input[i]  16)  0xFF;

output[j+3] = (input[i]  24)  0xFF;

i++;

j+=4;

}

}

void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len)

{

unsigned int i = 0,j = 0;

while(j  len)

{

output[i] = (input[j]) |

(input[j+1]  8) |

(input[j+2]  16) |

(input[j+3]  24);

i++;

j+=4; 

}

}

void MD5Transform(unsigned int state[4],unsigned char block[64])

{

unsigned int a = state[0];

unsigned int b = state[1];

unsigned int c = state[2];

unsigned int d = state[3];

unsigned int x[64];

MD5Decode(x,block,64);

FF(a, b, c, d, x[ 0], 7, 0xd76aa478); /* 1 */

FF(d, a, b, c, x[ 1], 12, 0xe8c7b756); /* 2 */

FF(c, d, a, b, x[ 2], 17, 0x242070db); /* 3 */

FF(b, c, d, a, x[ 3], 22, 0xc1bdceee); /* 4 */

FF(a, b, c, d, x[ 4], 7, 0xf57c0faf); /* 5 */

FF(d, a, b, c, x[ 5], 12, 0x4787c62a); /* 6 */

FF(c, d, a, b, x[ 6], 17, 0xa8304613); /* 7 */

FF(b, c, d, a, x[ 7], 22, 0xfd469501); /* 8 */

FF(a, b, c, d, x[ 8], 7, 0x698098d8); /* 9 */

FF(d, a, b, c, x[ 9], 12, 0x8b44f7af); /* 10 */

FF(c, d, a, b, x[10], 17, 0xffff5bb1); /* 11 */

FF(b, c, d, a, x[11], 22, 0x895cd7be); /* 12 */

FF(a, b, c, d, x[12], 7, 0x6b901122); /* 13 */

FF(d, a, b, c, x[13], 12, 0xfd987193); /* 14 */

FF(c, d, a, b, x[14], 17, 0xa679438e); /* 15 */

FF(b, c, d, a, x[15], 22, 0x49b40821); /* 16 */