1.无缓冲channel
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package main
import (
"fmt"
"time"
)
var message = make(chan string)
//往channel中输入信息
func sample1() {
message <- "hello gorotine."
}
//消费channel中的信息
func sample2() {
str := <- message
str = str + " run fast,run the world."
message <- str
}
func main() {
go sample1()
go sample2()
time.Sleep(time.Second)
fmt.Println(<-message)
fmt.Println("message")
}
2.buffer channel(缓冲channel)
package main
import (
"fmt"
"time"
)
/*
1.buffer channel
2.在函数中传递channel,而不是申明一个全局变量channel
3.FIFO:first input first output
*/
//往channel中输入信息
func sample1(message chan string) {
message <- "hello gorotine.1"
message <- "hello gorotine.2"
message <- "hello gorotine.3"
message <- "hello gorotine.4"
}
//消费channel中的信息
func sample2(message chan string) {
str := <- message
str = str + " run fast,run the world."
message <- str
}
func main() {
var message = make(chan string, 4)
go sample1(message)
go sample2(message)
time.Sleep(time.Second)
fmt.Println(<-message)
fmt.Println(<-message)
fmt.Println(<-message)
//fmt.Println(<-message)
fmt.Println("message")
}
// 2.1 output1
hello gorotine.2
hello gorotine.3
hello gorotine.4
message
取消这行代码的注释//fmt.Println(<-message),将会得到如下的输出,这正好说明了先进先出的概念
//2.2 output2
hello gorotine.2
hello gorotine.3
hello gorotine.4
hello gorotine.1 run fast,run the world.
message
3.遍历channel及关闭遍历channel
package main
import (
"fmt"
"time"
)
/*
1.buffer channel
2.在函数中传递channel,而不是申明一个全局变量channel
3.FIFO:first input first output
*/
//往channel中输入信息
func sample1(message chan string) {
message <- "hello gorotine.1"
message <- "hello gorotine.2"
message <- "hello gorotine.3"
message <- "hello gorotine.4"
}
//消费channel中的信息
func sample2(message chan string) {
str := <- message
str = str + " run fast,run the world."
message <- str
}
func main() {
var message = make(chan string, 4)
go sample1(message)
go sample2(message)
time.Sleep(time.Second)
//使用range遍历channel
for str := range message {
fmt.Println(str)
}
fmt.Println("message")
}
不关闭channel,那么channel默认为空;那此时如果遍历,则会抛出异常
//3.1output1
hello gorotine.2
hello gorotine.3
hello gorotine.4
hello gorotine.1 run fast,run the world.
fatal error: all goroutines are asleep - deadlock!
goroutine 1 [chan receive]:
main.main()
D:/run/pms/src/test.go:37 +0x126
下面演示关闭channel的遍历
package main
import (
"fmt"
"time"
)
/*
1.buffer channel
2.在函数中传递channel,而不是申明一个全局变量channel
3.FIFO:first input first output
*/
//往channel中输入信息
func sample1(message chan string) {
message <- "hello gorotine.1"
message <- "hello gorotine.2"
message <- "hello gorotine.3"
message <- "hello gorotine.4"
}
//消费channel中的信息
func sample2(message chan string) {
str := <- message
str = str + " run fast,run the world."
message <- str
close(message)
}
func main() {
var message = make(chan string, 4)
go sample1(message)
go sample2(message)
time.Sleep(time.Second)
//使用range遍历channel
for str := range message {
fmt.Println(str)
}
fmt.Println("message")
}
//3.2output2
hello gorotine.2
hello gorotine.3
hello gorotine.4
hello gorotine.1 run fast,run the world.
message