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Python怎么从sql提取表名
ply:词法语法解析模块;
re:正则表达式模块。
全部代码如下:
import ply.lex as lex, re def extract_table_name_from_sql(sql_str): # remove the /* */ comments q = re.sub(r"/\*[^*]*\*+(?:[^*/][^*]*\*+)*/", "", sql_str) # remove whole line -- and # comments lines = [line for line in q.splitlines() if not re.match("^\s*(--|#)", line)] # remove trailing -- and # comments q = " ".join([re.split("--|#", line)[0] for line in lines]) # split on blanks, parens and semicolons tokens = re.split(r"[\s)(;]+", q) # scan the tokens. if we see a FROM or JOIN, we set the get_next # flag, and grab the next one (unless it's SELECT). result = [] get_next = False for token in tokens: if get_next: if token.lower() not in ["", "select"]: result.append(token) get_next = False get_next = token.lower() in ["from", "join"] return result sql2="SELECT a.time_updated_server/1000,content,nick,name FROM " \ "table1 a JOIN " \ "table2 b ON a.sender_id = b.user_id JOIN table3 c ON a.channel_id = c.channel_id JOIN table4 d ON c.store_id = d.store_id WHERE sender_id NOT IN(SELECT user_id FROM table5 WHERE store_id IN ('agent_store:1', 'ask:1')) AND to_timestamp(a.time_updated_server/1000)::date >= '2014-05-01' GROUP BY 1,2,3,4 HAVING sum(1) > 500 ORDER BY 1 ASC" print(extract_table_name_from_sql(sql2))
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