谁能给一个Java程序代码我，要50行到100行就可以啦。最好有几行解释
给你一个前几天才帮人写的
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“计算整钱兑零”。程序要求用户输入一个双精度数代表总元数，就会列出总值与其等价的1元币、二角五分币、5分币和1分币的数目。程序报告的数目是1元币的最大数、其次是二角五分币的最大数，等等，依此类推。只显示非零的单位。对单个单位显示单数单词，对多于一个单位的显示复数单词
import java.util.Scanner;
public class MoneyCalculate {
public static void main(String[] args) {
int max100 = 0;
int max25 = 0;
int max5 = 0;
int max1 = 0;
double money = getMoneyFromInput();
String str = String.valueOf(money).trim();
String[] ary = str.split("\\.");
max100 = Integer.parseInt(ary[0]);
if(ary.length == 2){
int fen = Integer.parseInt(ary[1]);
if(ary[1].trim().length() == 1){
fen = Integer.parseInt(ary[1]) * 10;
}
max25 = fen / 25;
if(fen % 25 != 0){
fen = fen % 25;
}else{
fen = 0;
}
max5 = fen / 5;
max1 = fen % 5;
}
StringBuilder sb = new StringBuilder(money + " = ");
if(max100 != 0){
sb.append(max100);
sb.append("*1 ");
}
if(max25 != 0){
sb.append(max25);
sb.append("*0.25 ");
}
if(max5 != 0){
sb.append(max5);
sb.append("*0.05 ");
}
if(max1 != 0){
sb.append(max1);
sb.append("*0.01 ");
}
System.out.println(sb.toString());
}
private static double getMoneyFromInput() {
Scanner scanner = new Scanner(System.in);
return scanner.nextDouble();
}
}
-----------
2.49
2.49 = 2*1 1*0.25 4*0.05 4*0.01
-----------
2.5
2.5 = 2*1 2*0.25
-----------
37.23
37.23 = 37*1 4*0.05 3*0.01
-----------------
123.569
123.569 = 123*1 22*0.25 3*0.05 4*0.01
Java斐波那契数第35个数，流程图加代码？
流程图如下：
public int Fibonacci(int n) {
int[] res = {0, 1};
if(n 2) {
return res[n];
}
int first = 0;
int second = 1;
int fibn = 0;
for(int i = 2; i = n; i++) {
fibn = first + second;
first = second;
second = fibn;
}
return fibn;
}
public static void main(String[] args) {
System.out.println(Fibonacci(35));
}
java代码，给我写个
import javax.swing.JOptionPane;
class Rectangle extends Shape
{
public double zhouchang(double c,double k)
{
return (c + k) * 2;
}
public double mianji(double c,double k)
{
return c * k;
}
}
class Square extends Shape
{
public double zhouchang(double c,double k)
{
return (c + k) * 2;
}
public double mianji(double c,double k)
{
return c * k;
}
}
class Circle extends Shape
{
public double zhouchang(double y,double P)
{
return P * y * 2;
}
public double mianji(double y,double P)
{
return P * y * P * y;
}
}
abstract class Shape
{
public abstract double zhouchang(double x,double y);
public abstract double mianji(double x,double y);
}
public class Wb5
{
public static void main(String[] dafdasdf)
{
final double P = 3.14;
System.out.println("输入长");
double c = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter Number"));
System.out.println("输入宽");
double k = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter Number"));
System.out.println("输入输入半径");
double y = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter Number"));
Rectangle a = new Rectangle();
double cf = a.zhouchang(c,k);
double cf1 = a.mianji(c,k);
System.out.println("长方形的周长为:"+cf);
System.out.println("长方形的面积为:"+cf1);
Square b = new Square();
double zf = b.zhouchang(c,k);
double zf1 = b.mianji(c,k);
System.out.println("正方形的周长为:"+zf);
System.out.println("正方形的面积为:"+zf1);
Circle d = new Circle();
double yy = d.zhouchang(y,P);
double yy1 = d.mianji(y,P);
System.out.println("圆形的周长为:"+yy);
System.out.println("圆形的面积为:"+yy1);
}
}
35选7 用java代码实现
public class mainClass {
public mainClass() {
}
public static void main(String []args){
int [] num = new int[35];
boolean [] flag = new boolean[35];
int count = 0;
for(int i=0;i35;i++)
{
num[i] = i + 1;
flag[i] = true;
}
while(count!=7){
int k=(int)(Math.random()*35);
if(flag[k]){
System.out.println(num[k]);
flag[k]=false;
count++;
}
}
}
}
本文标题：35个java代码的简单介绍
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